2x^2+2x=168

Solution for 2x^2+2x=168 equation:

2x^2+2x=168

We move all terms to the left:

2x^2+2x-(168)=0

a = 2; b = 2; c = -168;
Δ = b2-4ac
Δ = 22-4·2·(-168)
Δ = 1348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1348}=\sqrt{4*337}=\sqrt{4}*\sqrt{337}=2\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{337}}{2*2}=\frac{-2-2\sqrt{337}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{337}}{2*2}=\frac{-2+2\sqrt{337}}{4}
$